If log 2 = 0.3010 and log 3 = 0.4771 , then the value of log 24 is:

Option c: 1.3801. Solution: 24 = 23 × 3 log 24 = 3log 2 + log 3 = 3(0.3010) + 0.4771 = 0.9030 + 0.4771 = 1.3801 The answer is (c) 1.3801 .

If $\log 2 = 0.3010$ and $\log 3 = 0.4771$, then the value of $\log 24$ is:

The correct answer is Option c: $1.3801$. $$24 = 2^3 \times 3$$ $$\log 24 = 3\log 2 + \log 3$$ $$= 3(0.3010) + 0.4771$$ $$= 0.9030 + 0.4771$$ $$= 1.3801$$ **The answer is (c) $1.3801$.**

Ratio, Proportion, Indices, LogarithmMCQMTP Dec 23 Series IQuestion 977 of 305

All Questions

If $\displaystyle \log 2 = 0.3010$ and $\displaystyle \log 3 = 0.4771$ , then the value of $\displaystyle \log 24$ is:

Options

\displaystyle 1.0791

\displaystyle 1.7323

\displaystyle 1.3801

\displaystyle 1.8301

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Correct Answer

✅ Option c — $\displaystyle 1.3801$

All Options:

A $\displaystyle 1.0791$
B $\displaystyle 1.7323$
C $\displaystyle 1.3801$
D $\displaystyle 1.8301$

Detailed Solution & Explanation

24 = 2^3 \times 3

\log 24 = 3\log 2 + \log 3

= 3(0.3010) + 0.4771

= 0.9030 + 0.4771

= 1.3801

**The answer is (c)

\displaystyle 1.3801

.**

About This Chapter: Ratio, Proportion, Indices, Logarithm

Paper

Paper 3: Quantitative Aptitude

Weightage

5-7 Marks

Key Topics

Ratio, Proportion, Indices, Logarithms

This chapter covers Ratio, Proportion, Indices, Logarithms and is part of Paper 3: Quantitative Aptitude in the CA Foundation exam.

View Official ICAI Syllabus

Exam Strategy Tip

This topic carries 5-7 Marks weightage. Focus on understanding core concepts rather than memorizing.

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If log⁡2=0.3010\displaystyle \log 2 = 0.3010log2=0.3010 and log⁡3=0.4771\displaystyle \log 3 = 0.4771log3=0.4771, then the value of log⁡24\displaystyle \log 24log24 is: