Ratio, Proportion, Indices, LogarithmMCQMTP Sep 24 Series IIQuestion 982 of 305
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loga2bc+logb2ca+logc2ab=\displaystyle \log \frac{a^2}{bc} + \log \frac{b^2}{ca} + \log \frac{c^2}{ab} =

Options

A0\displaystyle 0
B1\displaystyle 1
Cloga\displaystyle \log a
DNone of these
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Correct Answer

Option a0\displaystyle 0

All Options:

  • A0\displaystyle 0
  • B1\displaystyle 1
  • Cloga\displaystyle \log a
  • DNone of these

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Detailed Solution & Explanation

Using the product rule of logarithms:

loga2bc+logb2ca+logc2ab=log(a2bcb2cac2ab)\log \frac{a^2}{bc} + \log \frac{b^2}{ca} + \log \frac{c^2}{ab} = \log\left(\frac{a^2}{bc} \cdot \frac{b^2}{ca} \cdot \frac{c^2}{ab}\right)

Multiply numerators: a2b2c2=a2b2c2\displaystyle a^2 \cdot b^2 \cdot c^2 = a^2 b^2 c^2

Multiply denominators: bccaab=a2b2c2\displaystyle bc \cdot ca \cdot ab = a^2 b^2 c^2

=log(a2b2c2a2b2c2)=log1=0= \log\left(\frac{a^2 b^2 c^2}{a^2 b^2 c^2}\right) = \log 1 = 0

**The answer is (a) 0.**

About This Chapter: Ratio, Proportion, Indices, Logarithm

Paper

Paper 3: Quantitative Aptitude

Weightage

5-7 Marks

Key Topics

Ratio, Proportion, Indices, Logarithms

This chapter covers Ratio, Proportion, Indices, Logarithms and is part of Paper 3: Quantitative Aptitude in the CA Foundation exam.

View Official ICAI Syllabus

Exam Strategy Tip

This topic carries 5-7 Marks weightage. Focus on understanding core concepts rather than memorizing.

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