If $\displaystyle n = m!$ where ($\displaystyle 'm'$ is a positive integer $\displaystyle > 2$) then the value of: $\displaystyle \frac{1}{\log_2 n} + \frac{1}{\log_3 n} + \frac{1}{\log_4 n} + \dots + \frac{1}{\log_m n}$

$\displaystyle 3x-2:5x+6$ the duplicate ratio of $\displaystyle 2:3$ then find the value $\displaystyle x$.

If the ratio of two numbers is $\displaystyle 7:11$. If $\displaystyle 7$ is added to each number then the new ratio will be $\displaystyle 2:3$ then the numbers are.

If $\displaystyle x:y=z:7=4:11$ then $\displaystyle \frac{x+y+z}{z}$ is

The ratio of two numbers are $\displaystyle 3:4$. The difference of their squares is $\displaystyle 28$ greater is:

The price of scooter and moped are in the ratio $\displaystyle 7:9$. The price of moped is $\displaystyle ₹1,600$ more than that of scooter. Then the price of moped is:

If $\displaystyle A:B=3:7$, then $\displaystyle 3a+2b:4a+5b=?$